nder alkaline conditions, mesoporous molecular sieve Ce-MCM-41 was successfully synthesized by using sodium metasilicate as aluminum source, cerium nitrate as cerium source, and cetyltrimethylammonium bromide (CTAB) as structural template. The synthesized Ce-MCM-41 molecular sieve was characterized by XRD and FT-IR. XRD and FT-IR characterization results indicated that Ce atom had entered the framework of MCM-41. The Ce-MCM-41 molecular sieve was used to adsorb and separate nitrides in the oil products. The factors which had a significant effect on the denitrification rate and the optimum technological conditions in certain parameters range were studied. The results show that the optimum conditions for the denitrogenation of simulated oil by Ce-MCM-41 molecular sieve are: 3.0 hours of adsorption time, 80 ℃ of adsorption temperature, 20 mass ratio of oil, the denitrification rate is 85.67%.

With CTAB as template, the β/MCM-41 micro-mesoporous composite molecular sieve has been synthesized by self-assembly of the zeolite structure fragments and the structural units obtained by alkali-treated β zeolite, and the effects of the alkali solution concentration, CTAB dosage in the synthesis process of β/MCM-41 was investigated. The β/MCM-41 composite molecular sieve with well long-range order can be synthesized under the optimum conditions: The solution concentration of NaOH is 1.5 mol/L and the mass fraction of CTAB is 10%. Then the Ce- β/MCM-41 composite molecular sieve doped skeleton with rare earth metal Ce was synthesized and the effect of Ce doping amount (Ce/ β=0.03, 0.08) on Ce- β/MCM-41 was investigated. The result shows that the 0.03-Ce- β/MCM-41 had a well long-range order. The effect of acetylation reaction conditions on the yield of p-MOAP was investigated by using 0.03-Ce- β/MCM-41 as a catalyst in a fixed bed. The single-factor experiments showes that the 4.0 h p-MOAP yield is 58.6% under the conditions: The velocity of the reactants flow is 65 mL/h, the LHSV is 6.5 h ^-1, reaction temperature is 140 ℃ and n(AN)/n(AA)=6.0.